Let?s explain.I can?t see Pathfinder in the soil.Instead,I go to near the 0.00m mark,then the screen became black and down below,is Pathfinder.There is no mark seeing for above like "Pathfinder".And around Pathfinder,there is the black sky,the Sun,...
I don?t understand if the probe is "inside" Mars or if it?s simply in the space.
I am using redmars VT(8k texture from Praesepe)
Pathfinder localized inside Mars!
-
- Developer
- Posts: 1863
- Joined: 21.11.2002
- With us: 22 years
This is, I'm sure, the result of a change in the defined radius for Mars between 1.3.0 and 1.3.1. Sorry!
After a number of complaints about inaccurate or outdated dimensions for solar system bodies, I took a run through and updated/refined the figures. The equatorial radius of Mars was updated from 3394km to 3396km, which will almost certainly have left Pathfinder 2km below the surface.
You should be able to fix this on the fly by opening the relevant ssc, and multiplying the SemiMajorAxis figures you find there by 3396/3394 = 1.00059.
For the information of add-on builders, the Moon and Venus are unchanged, but Earth has been refined from 6378 to 6378.14km. I'd hope that if Chris gives us a means of placing a body directly at a specified location (instead of having to use my elaborate orbital hack), this'll be independent of the specified radius, and so will avoid all this hassle.
Grant
After a number of complaints about inaccurate or outdated dimensions for solar system bodies, I took a run through and updated/refined the figures. The equatorial radius of Mars was updated from 3394km to 3396km, which will almost certainly have left Pathfinder 2km below the surface.
You should be able to fix this on the fly by opening the relevant ssc, and multiplying the SemiMajorAxis figures you find there by 3396/3394 = 1.00059.
For the information of add-on builders, the Moon and Venus are unchanged, but Earth has been refined from 6378 to 6378.14km. I'd hope that if Chris gives us a means of placing a body directly at a specified location (instead of having to use my elaborate orbital hack), this'll be independent of the specified radius, and so will avoid all this hassle.
Grant