Swine Flu
Posted: 19.05.2009, 20:10
Perhaps some of you are interested in a more quantitative statement about the spreading of the Swine Flu (H1N1) infections worldwide with time and the corresponding behaviour of fatalities (red curve).
I plotted the following first 19 days since the outbreak using the official numbers from the WHO.
[EDIT:] For an updated and much improved diagram see further below!
As a rule of thumb, during about 2 weeks, the number of infections almost doubled within 4 days. As long as this law would hold, we face an exponential growth which sounds frightening! An exponential growth would correspond to a straight line growth in this semi-logarithmic plot. As you can see, the growth is less than linear overall (fortunately for now).
Some background math:
----------------------------------
Suppose, we have a law:
n = const. * a^t
and a doubling of the infection rate n2/n1 = 2 in t2 - t1 = 4 days
n2/n1 = a^(t2 - t1) = a^4 = 2
This determines a
a = 2^(1/4)
Therefore, a doubling every 4 days indeed corresponds to an exponential growth!
+++++++++++++++++++++++++++++++++++++
n = const. * 2 ^(t/4) = const. exp (ln(2)/4 *t) ; with t expressed in days.
+++++++++++++++++++++++++++++++++++++
More recently, however, the growth might show a tendency of flattening out...
Fridger
I plotted the following first 19 days since the outbreak using the official numbers from the WHO.
[EDIT:] For an updated and much improved diagram see further below!
As a rule of thumb, during about 2 weeks, the number of infections almost doubled within 4 days. As long as this law would hold, we face an exponential growth which sounds frightening! An exponential growth would correspond to a straight line growth in this semi-logarithmic plot. As you can see, the growth is less than linear overall (fortunately for now).
Some background math:
----------------------------------
Suppose, we have a law:
n = const. * a^t
and a doubling of the infection rate n2/n1 = 2 in t2 - t1 = 4 days
n2/n1 = a^(t2 - t1) = a^4 = 2
This determines a
a = 2^(1/4)
Therefore, a doubling every 4 days indeed corresponds to an exponential growth!
+++++++++++++++++++++++++++++++++++++
n = const. * 2 ^(t/4) = const. exp (ln(2)/4 *t) ; with t expressed in days.
+++++++++++++++++++++++++++++++++++++
More recently, however, the growth might show a tendency of flattening out...
Fridger