C/2001 Q4

[symaski62]

Code: Select all

"C/2001 Q4" "Sol"
{
  Class      "comet"
  Texture    "asteroid.jpg"
  Mesh       "asteroid.cms"
  Radius      ????

  EllipticalOrbit
  {
    Period                 ????
    SemiMajorAxis          ????
    Eccentricity           1.000522818
    Inclination            99.6423878
    AscendingNode          210.2786496
    ArgOfPericenter        1.207514
    MeanAnomaly            359.9997506
    Epoch                  2453141.4684405
  }
}

http://neo.jpl.nasa.gov/cgi-bin/db_shm?sstr=C%2F2001+Q4&group=all
merci i am french

[granthutchison]

Code: Select all

"C/2001 Q4" "Sol"
{
  Class      "comet"
  Texture    "asteroid.jpg"
  Mesh       "asteroid.cms"
  Radius      5 #???

  EllipticalOrbit
  {
    Period                 78923.351
    PericenterDistance     0.961953788     
    Eccentricity           1.000522818
    Inclination            99.6423878
    AscendingNode          210.2786496
    ArgOfPericenter        1.207514
    MeanAnomaly            0
    Epoch                  2453141.4684405
  }
}

http://www.lns.cornell.edu/~seb/celestia/transforming_ephemeris.html

Grant

[symaski62]

Period #calculated: (q/(1-e))**1.5

[granthutchison]

Period #calculated: (q/(e-1))**1.5

Mean motion (n) for hyperbolic orbits = ((e-1)/q)^1.5

"Period" used by Celestia is the inverse of mean motion.

Grant

[symaski62]

je suis mal

((1-1.000522818)/0.961953788)^1.5 = error

moi fran?ais


merci

[granthutchison]

Je m'excuse – pour des orbites hyperboliques c'est (1-e), pas (e-1).

Grant

[symaski62]

error VU rien

je vois l'ordinature avec "calc"


((1-Eccentricity)/PericenterDistance)^1.5

((1-1.000522818)/0.961953788)^1.5

((-0.000522818)/0.961953788)^1.5

-5.434959626^1.5 = -12.67052130


VU

[granthutchison]

Aaargh! J'avais raison la primi?re fois - c'est (e-1) pour des orbites hyperboliques:

(PericenterDistance/(Eccentricity-1))^1.5

= (0.961953788/0.000522818)^1.5

= 1839.940071^1.5

= 78923.351 (ann?es)

Grant

[Guest]

merci beaucoup!!!!

[symaski62]

merci beaucoup!!

[Guest]

Does anybody took a picture (or more) of C/2001 Q4 in the last days?

[ElPelado]

There are many pictures in teh internet
here you have one:

[Adirondack]

Does anybody took a picture (or more) of C/2001 Q4 in the last days?

Well, as I understand the question, Mr. Guest means photographs that somebody of us made of C/2001 Q4.
Did somebody?